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0.4-10.97x-4.91x^2=0
a = -4.91; b = -10.97; c = +0.4;
Δ = b2-4ac
Δ = -10.972-4·(-4.91)·0.4
Δ = 128.1969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.97)-\sqrt{128.1969}}{2*-4.91}=\frac{10.97-\sqrt{128.1969}}{-9.82} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.97)+\sqrt{128.1969}}{2*-4.91}=\frac{10.97+\sqrt{128.1969}}{-9.82} $
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